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Retry requests on server error
******************************
If lazr.restfulclient talks to a server that sends out a server-side
error with status codes 502 or 503, the client will wait a few seconds
and try the request again. Eventually it will give up and escalate the
error code in the form of an exception.
To test this, let's simulate a lazr.restful server prone to transient
errors using a WSGI application.
>>> import pkg_resources
>>> wadl_string = pkg_resources.resource_string(
... 'wadllib.tests.data', 'launchpad-wadl.xml')
>>> representations = { 'application/vnd.sun.wadl+xml' : wadl_string,
... 'application/json' : '{}' }
This application will cause one request to fail for every item in its
BROKEN_RESPONSES list.
>>> BROKEN_RESPONSES = []
>>> def broken_application(environ, start_response):
... if len(BROKEN_RESPONSES) > 0:
... start_response(str(BROKEN_RESPONSES.pop()),
... [('Content-type', 'text/plain')])
... return ["Sorry, I'm still broken."]
... else:
... media_type = environ['HTTP_ACCEPT']
... content = representations[media_type]
... start_response(
... '200', [('Content-type', media_type)])
... return [content]
>>> def make_broken_application():
... return broken_application
>>> import wsgi_intercept
>>> wsgi_intercept.add_wsgi_intercept(
... 'api.launchpad.dev', 80, make_broken_application)
>>> BROKEN_RESPONSES = []
>>> from wsgi_intercept.httplib2_intercept import install
>>> install()
Here's a fake implementation of time.sleep() so that this test doesn't
take a really long time to run, and so we can visualize sleep() being
called as lazr.restfulclient retries over and over again.
>>> def fake_sleep(time):
... print "sleep(%s) called" % time
>>> import lazr.restfulclient._browser
>>> old_sleep = lazr.restfulclient._browser.sleep
>>> lazr.restfulclient._browser.sleep = fake_sleep
As it starts out, the application isn't broken at all.
>>> from lazr.restfulclient.resource import ServiceRoot
>>> client = ServiceRoot(None, "http://api.launchpad.dev/")
Let's queue up one broken response. The client will sleep once and
try again.
>>> BROKEN_RESPONSES = [502]
>>> client = ServiceRoot(None, "http://api.launchpad.dev/")
sleep(0) called
Now the application will fail six times and then start working.
>>> BROKEN_RESPONSES = [502, 503, 502, 503, 502, 503]
>>> client = ServiceRoot(None, "http://api.launchpad.dev/")
sleep(0) called
sleep(1) called
sleep(2) called
sleep(4) called
sleep(8) called
sleep(16) called
Now the application will fail seven times and then start working. But
the client will give up before then--it will only retry the request
six times.
>>> BROKEN_RESPONSES = [502, 503, 502, 503, 502, 503, 502]
>>> client = ServiceRoot(None, "http://api.launchpad.dev/")
Traceback (most recent call last):
...
ServerError: HTTP Error 502:
...
By increasing the 'max_retries' constructor argument, we can make the
application try more than six times, and eventually succeed.
>>> BROKEN_RESPONSES = [502, 503, 502, 503, 502, 503, 502]
>>> client = ServiceRoot(None, "http://api.launchpad.dev/",
... max_retries=10)
sleep(0) called
sleep(1) called
sleep(2) called
sleep(4) called
sleep(8) called
sleep(16) called
sleep(32) called
Now the application will fail once and then give a 400 error. The
client will not retry in hopes that the 400 error will go away--400 is
a client error.
>>> BROKEN_RESPONSES = [502, 400]
>>> client = ServiceRoot(None, "http://api.launchpad.dev/")
Traceback (most recent call last):
...
BadRequest: HTTP Error 400:
...
Teardown.
>>> _ = wsgi_intercept.remove_wsgi_intercept("api.launchpad.dev", 80)
>>> lazr.restfulclient._browser.sleep = old_sleep